X² + X - 42=0
tolong jawab pake cara ya....
tolong jawab pake cara ya....
[tex]x {}^{2} + x - 42 = 0 \\ (x + 7)(x - 6) = 0 \\ \\ x + 7 = 0 \\ x1 = - 7 \\ \\ x - 6 = 0 \\ x2 = 6 \\ [/tex]
HP = {-7,6}
a = 1
b = 1
c = -42
[tex]7 - 6 = 1[/tex]
.
[tex] {x}^{2} + x - 42 = 0[/tex]
[tex](x + 7)(x - 6)[/tex]
[tex]x = - 7 \: atau \: x = 6[/tex]
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